Question

if log 2=0.3010 then find the number of digits in 2^1024​

Answer 1

Applying log (here base 10) to 2^1024 gives :

log(2^1024) = 1024*log2 = 1024*0.301 = 308.224

Now, to get the answer we have to apply antilog to the above result.

Applying antilog to 308.224 gives 308+1 = 309 digits answer starting with 1675……….

( 1 should be added to characteristic of the result after applying antilog to get the position of decimal place)

So, 309 digits will be there in 2^1024