If log 2 = 0.30103, the number of digits in 264 is:
A. 18 B. 19
C. 20 D. 21
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It should be
Let x =
Log x =
Logx = 64(log2)
logx = 64(0.30103)
logx = 19.26592
The characteristic of x is 19
Therefore, there are 20 (19+1) digits in
Let x =
Log x =
Logx = 64(log2)
logx = 64(0.30103)
logx = 19.26592
The characteristic of x is 19
Therefore, there are 20 (19+1) digits in
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