Question

if log 2=a and log 3=b then express log 60 in terms of a and b

Answer 1

Answer:

log60=log2tothe power of2+log3+log5

Step-by-step explanation:

log2=a, log3=b. Then a to the power of 2+b+logab

Answer 2

The value of log 60 in terms of a and b is (a+b+1).

Step-by-step explanation:

Given information:

$\log2=a,\log3=b$

We need to find the value if log 60 in terms of a and b.

$\log(60)=\log(2\times 3\times 10)$

Using the property of logarithm we get

$\log(60)=\log(2)+\log(3)+\log(10)$     $[\because \log(ab)=\log a+\log b]$

Substitute $\log2=a,\log3=b$.

$\log(60)=a+b+\log(10)$

We know that $\log10=1$.

$\log(60)=a+b+1$

Therefore, the value of log 60 in terms of a and b is (a+b+1).

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