Question

If log 2 base 10 =0.3010 & log 3 base 10=0.4771, find the value of log 2.25 base 10:
b. 0.3422
c.0.3522
d.0.3755
a. 0.3255​

Answer 1

Answer:

C. 0.3522

Step-by-step explanation:

2.25 = 3/2 × 3/2

log2.25 = log (3/2× 3/2) = log ( 3/2)² = 2log 3/2 = 2× (log 3 - log 2 )=2( 0.4771-0.3010) = 2(0.1761) = 0.3522

laws used : log a^n = nlog a

loga / logb = log a - logb