If log_{2}(log_{2}(log_{3^x})]=1
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Answer:
x = 4×log_3 ( 2 )
For explaination , please refer to the attachment .
Note:
★ log_b ( N ) = a => N = b^a
★ log(a×b) = log( a ) + log( b )
★ log(a/b) = log( a ) - log( b )
★ logNⁿ = n×logN
★ log_bⁿ ( N ) = (1/n)×log_b ( N )
★ log_b ( a ) = 1 / log_a ( b )
★ log_b ( a ) = [log_b ( k )]×[log_k ( a )]
★ log_b ( b ) = 1
★ log 1 = 0
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