Question

if log ( 2+ log base 2 x+1) = 0 find the value of x ?
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Answer 1

Step-by-step explanation:

I presume you mean to solve it when it equals 0.

Log= log (base 10)

Log (Log (2+Log (base 2) (X+1)))=0

We know that for any Y>0 : if Log (Y) =0 then Y=1

so: Log (2+Log (base 2) (X+1))=1

and we know that : Log (Base z)( X)= 1 then X=z

So: 2+Log (base 2) (X+1)=10 ===> Log (base 2) (X+1)=8

To cancel the logarithm you have to introduce the base of this logarithm such as: 2^log (base ) (X)=X

so: X+1= 2^8

then: X=256–1=255

Here. I hope this helps