Question

if log 2= x and log 3= y then

log 1 + log (1+3) + log (1+3+5) + ....... + log (1+3+5+7+9+11+13+15+17+19) - 2 [log 1 + log 2 + log 3 + ...... log 7] = a+bx+cy

where a,b,c are positive integers, find (a,b,c)

Please I need a proper explanation for your answer. At least let the ones who know the answer explain, don't keep useless answer for points! I need the answer desperately, please answer fast! ​

Answer 1

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if log 2= x and log 3= y then

log 1 + log (1+3) + log (1+3+5) + ....... + log (1+3+5+7+9+11+13+15+17+19) - 2 [log 1 + log 2 + log 3 + ...... log 7] = a+bx+cy

Answer 2

Answer:

hope it helps u.............