If log 25 = a log 75 = b then express log 9 and log 2 interms of a and b
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Answer:
log 9 = 2(b - a)
and log 5 = a/2
Step-by-step explanation:
Given ,
log 25 = a
→log5² = a
→2log5 = a
→log5 = a/2
And ,
log 75 = b
→ log(25×3)=b
→log5² + log 3 = b
→ 2log5+log 3 = b
→a + log 3 = b [ since 2log5 = a]
→log3 = b - a
Now we have :
log 9
= log3²
= 2log3
= 2(b - a)
or 2b - 2a
Note : It seems like there is something wrong in the question . We are given the values : log25 = a and log 75 = b . By these values we can express log 9 and log 5 in terms of a and b . But it is impossible to express log 2 in terms of a and b with given value .
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