Question

if log 27=1.431then the value of log 81 is​

Answer 1

Answer:

$\sf{The\: \:value \:\:of\: \:log 81\: \:is\: \:1.908.}$

Step-by-step explanation:

${\underline{\sf{ <u>Given</u><u> </u><u>\</u><u>:</u><u>\</u><u>:</u><u> </u><u>that</u><u>,</u><u> </u>}}}$

• $\sf{log \: 27 = 1.431}$

$\longrightarrow \sf \: log(_3 {}^{3} ) = 1.431 \\ \\ \longrightarrow \sf \:3log3 = 1.431 \\ \\ \longrightarrow \sf \: log3 = \frac{1.431}{3} \\ \\ \longrightarrow \sf \green{log3 = 0.477}$

${\underline{\sf{ Now, }}}$

• $\sf{log \: 81 = ? }$

$\longrightarrow \sf \:log_{81} = log(_3 {}^{4} ) = 4log_3 \\ \\ { \red{ \sf[ °.° \:log_3 = 0.477 ]}} \\ \\ \longrightarrow \sf \:log_{81} = 4 \times 0.477 \\ \\ \longrightarrow{ \boxed{\purple{ \sf{log_{81} = 1.908} }}} \: \green \bigstar$

Answer 2

Answer:

log81=1.9.8

Step-by-step explanation:

Given log27=1.431

          log( 3³)=1.431

          3log3=1.431             (as logmⁿ=nlogm)

          log3=1.431/3=0.477

now, log81= log(3⁴)

                  =4log3

                  =4×0.477

   So,      log81  =1.908

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