Question

if log√27x=8/2 find x​

Answer 1

$heya \\ \\ log( \sqrt{27} \times x) = 8 \div 2 \\ \\ log( \sqrt{27} ) + log(x) = 4 \\ becoz \: \: log(mn) = log(m) + log(n) \\ \\ log(3 {}^{3 \div 2} ) + log(x) = 4 \\ \\ (3 \div 2) log(3) + log(x) = 4 \\ becoz \: log(y {}^{t} ) = t log(y) \\ \\ log(x) = log(10 {}^{4} ) - (3 \div 2) log(3 ) \\ becoz \: \: log(10 {}^{ 4} ) = 4 log(10) = 4 \\ \\ log(x) = log((10 {}^{4} \div \sqrt{27} ) \\ \\ x = (10 {}^{4} \div \sqrt{27} ) \\ \\ x = (10 {}^{4} \div 3 \sqrt{3} )$

Answer 2

x=e4/√27

hope it will help you