Question

If log√27x=8/3 find value of x

Answer 1

answer :----

=/27x=8/3

=/9x=8

x=8/root9.....

hope it will help you

Plz mark as BRIANLIEST

Answer 2

Correct question is "If $log_{ \sqrt{27} }(x) = \frac{8}{3}$then find value of x"

Answer:

Required value of x is 81.

Step-by-step explanation:

Given,

$log_{ \sqrt{27} }(x) = \frac{8}{3} \\ x = {( \sqrt{27}) }^{ \frac{8}{3} } \\ x = ({27}^{ \frac{1}{2} } )^{ \frac{8}{3} } \\ x = ({ {3}^{3} }^{ \frac{1}{2} } )^{ \frac{8}{3} } \\ x = ({3}^{ \frac{3}{2} } )^{ \frac{8}{3} } \\ x = {3}^{ \frac{3}{2} \times \frac{8}{3} } \\ x = {3}^{4} \\ x = 81$

Here applied formula is

$log_{a}(x) = b \\ x = {a}^{b}$

Some important Logarithm formulas are

$log_{x}(1) = 0 \\ log_{x}(0) = 1 \\ log_{x}(y) = \frac{ log(x) }{ log(y) } \\ log( {x}^{y} ) = y log(x) \\log(x) + log(y) = log(xy) \\ log(x) - log(y) = log( \frac{x}{y} ) \\ log_{x}(x) = 1$

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