If log (2a - 3b) = log a-log b, then a is
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log (2a - 3b) = log (a/b)
2a - 3b = a/b
2ab - 3b² = a
2ab - a = 3b²
a(2b - 1) = 3b²
a = 3b²/(2b - 1)
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