Question

If log 3=0.48and log 7=0.84,then the value of log 0.03/0.7If log 3=0.48and log 7=0.84,then the value of log 0.03/0.7

Answer 1

Answer:

log 0.03/0.7

= log (3×10^-2/7×10^-1)

= log3-log7+log10^-1

= 0.48-0.84-1

= -1.36

Answer 2

Answer:

-1.36

Step-by-step explanation:

GIVEN:- log3 = 0.48 and log7 = 0.84

now, log0.03 /0.7 = log 3×10-²/7×10-¹

where, loga/b = loga - logb

logm×n = logm + logn

=> log(3×10-² )- log(7×10-¹)

=> log3 + log1/100 - log7 - log1/10

=> 0.48 - 0.84 + log{(1/100) /(1/10)}

=> -0.36 + log1/10

=> - 0.36 + log1 - log10

=> -0.36 + 0 - 1

=> -1.36

therefore, log0.03/0.7 = -1.36

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