If log 3.16=2.49776 then antilog2497. 76
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Answer:
The given equation is:
\frac{cos20+sin20}{cos20-sin20}=tan65
Taking the left hand side of the above equation, we get
\frac{cos20+sin20}{cos20-sin20}
\frac{cos20(1+\frac{sin20}{cos20})}{cos20(1-\frac{sin20}{cos20})}
\frac{1+tan20}{1-tan20}
Now, we know that tan45=1, therefore the above equation becomes,
\frac{tan45+tan20}{tan45-tan20}
Using, tan(A+B)=\frac{tanA+tanB}{1-tanAtanB}, the above equation becomes,
tan(45+20)
tan65=RHS
Hence proved.
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