if log 3 to the base 30=a,log 5 to thhe base 30=b,then find the value of log 32 to the base 50 in terms of a and b
Answers
Answered by
3
Answer:
log
30
3=a and log
30
5=b
To find log
30
8, we will use log
30
30=1
⟹log
30
30=1
⟹log
30
(3×5×2)=1
⟹log
30
3+log
30
5+log
30
2=1
⟹a+b+log
30
2=1
⟹log
30
2=(1−a−b)
∴log
30
8=log
30
2
3
=3log
30
2=3(1−a−b)
Answered by
0
Answer:
30 x50 therefore we need to multiply 32 × 50
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