Question

if log 4 = 0.6020 then find value of log 80​

Answer 1

Step-by-step explanation:

log 80=log( 2^3×10)

=log 2^3+log 10

=3log2+1, since log 10=1.

=3×0.3010+1

=0.9030+1

=1.9030.

Answer 2

The value of log 80 = 1.903.

Step-by-step explanation:

Since we have given that

log 4 = 0.6020

We need to find the value of log 80.

As we know that

log m×n = log m + log n

So, it becomes,

$\log 80=\log (2\times 4\times 10)\\\\\log 80=\log 2+\log 4+\log 10\\\\\log 80=\dfrac{1}{2}\log 4+\log 4+1\\\\\log 80=\dfrac{1}{2}\times 0.6020+0.6020+1\\\\\log 80=0.3010+0.6020+1\\\\\log 80=1.903$

Hence, the value of log 80 = 1.903.

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if log 4 = 0.6020 then find value of log 80​

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