If log, 4
=
-1/3 then x =
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x=1/64
Step by step Explanation:
since the ques is not properly..so i'm assuming
log 4 and base x.
as,
㏒x(4) = -1/3 = -㏒x((x^(1/3)) [using ㏒a(a^n) = n]
㏒x(4) + ㏒x((x^(1/3))= 0
㏒x(4×(x^1/3))= 0 [simple addition property]
4×(x^1/3) = 1 [㏒a(n) = 0, then n = 1]
x^1/3 = 1/4
(x^1/3)^3 = (1/4)^3 [both side cubing]
x^1 = (1/4)^3 = 1/64
x = 1/64
I HOPE THIS HELPS YOU
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