Question

If log 5(x2 + 9) = 2 then find the value of x​

Answer 1

Answer:

$x_{12}$ = ± 4

Step-by-step explanation:

$log_{5}(x^2+9)=2$ ⇔ $5^{2} = x^2+9$

x² + 9 = 25

x² - 16 = 0

(x - 4)(x + 4) = 0

$x_{1} = 4$

$x_{2} = - 4$