Math, asked by zubairmatin7496, 1 year ago

If log 64 = 1.8061, then the value of log 16 will be (approx)?

Answers

Answered by swastipadhi13
2

Answer:

1.2040

Step-by-step explanation:

64= 2 ^ 6

log (64)= 1.8061

log(2^6)=1.8061

6* log (2)=1.8061

log (2)= 1.8061/ 6 ------ (i)

16=2^4

log (16)= log (2^4)

4* log (2)= (1.8061 * 4)/6 ------(ii)        {From (i)}

=1.2040

Hence, log(16)=1.2040

Answered by Anonymous
0

Given : Value of log 64 is 1.8061

To find : The value of log 16

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the value of log 16)

Here, we will be using general formula of logarithm.

So,

log 64 = 1.8061

log (4)³ = 1.8061

3 × log 4 = 1.8061

log 4 = 1.8061 ÷ 3

log 4 = 0.0602

2 × log 4 = 2 × 0.0602

log (4)² = 0.1204 (approx.)

log 16 = 0.1204

(This will be considered as the final result of the given mathematical problem.)

Used formula :

  • log xⁿ = n × log x

Hence, the approximate value of log 16 is 0.1204

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