Question

if (log 7- log 2 + log 16- 2log3-log 7/45)=1+log n find the value of n?
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Answer 1

Answer:

Step-by-step explanation:

By using the property of log we can write it as log(7*16*45/2*9 *7)=1+logn log 40 - log n=1 log40/n=1 40/n=antilog 1 n=40/antilog 1 n=40/10 n=4