Question

If logₓ9= -2, what is the value of X ?

Answer 1

Correct Question:

If logₓ9= 2, what is the value of X ?

Given :

• logₓ9= 2

To Find :

The value of X

Theory :

if logₓa = y, then in exponent form.

$\sf \: x {}^{y} = a$

Sôlútion:

$\sf log_{x}(9) = 2$

$\implies \sf \: x {}^{ 2} = 9$

$\implies \sf \: x {}^{ 2} = 3 {}^{2}$

Now on comparing ,

$\bf \: x = 3$

Properties of Logarithm:

$\sf \: log(x) + log(y) = log(xy)$

$\sf \: log(x) - log(y) = log( \frac{x}{y} )$

Answer 2

$\huge\mathfrak\pink{Question}$

If loₓ9= -2,

$\huge\mathfrak\pink{Solution}$

★ Given :-

• loₓ9= -2

★ To find :-

The value of x

★ Theory:-

If logₓ 9 = y, then in exponent form.

$x ^{y} \: = \: \: 9 \:$

$solution \:$

$loₓ(9)= 2$

$= > x^{2} = 9 \:$

$= > \: x ^{2} = 3 ^{2}$

$\red{Now \ on \ comparing}$

$x \: = 3$

$\red{properties \ of \ logarithm}$

$log(x) + log(y) \: = \: log(xy)$

$log(x) - log(y) = log( \frac{x}{y} )$