Question

if log(a^-a-20)=0, then find the value of a
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Answer 1

as we have,

log(a^-a-20) = 0

so,. log(a^-a-20) = log 1

so,,. a^-a-20 = 1

a^-a = 21

1/a^a = 21

so,. a^a = 1/21

taking log on both side

a loga = log1-log20

so,. a = -log20/loga. ans.