Question

If log a-b/2=1/2(log a+log b), show that: a^2+b^2 = 6ab

Answer 1

log ( a - b )/2 = 1/2 ( log a + log b )

2 log ( a - b ) /2 = log a + log b

log [ ( a - b )/2 ] ² = log ab

( a - b )²/2² = ab

( a - b )² = 4ab

a² + b² - 2ab = 4ab

a² + b² = 4ab + 2ab

a² + b² = 6ab

I hope this helps you

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