If log (a + b)^2 = log 9 + log a + log b, then a^2 + b^2 =
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Answered by
4
log (a+b)^2 = log (9*a*b)
log (a+b)^2= log (9ab)
(a+b)^2 = 9ab
__________________________________________
by formula, (a+b)^2 = a^2 +b^2 +2ab
_____________________________________________________
a^2 + b^2 +2ab = 9ab
a^2+b^2 = 9ab -2ab
a^2 + b^2 = 7ab
i hope this will help you
-by ABHAY
log (a+b)^2= log (9ab)
(a+b)^2 = 9ab
__________________________________________
by formula, (a+b)^2 = a^2 +b^2 +2ab
_____________________________________________________
a^2 + b^2 +2ab = 9ab
a^2+b^2 = 9ab -2ab
a^2 + b^2 = 7ab
i hope this will help you
-by ABHAY
Answered by
3
log(a+b)²=log 9+log a+log b
log(a²+b²+2ab)=log(9×a×b)
comparing both side
a²+b²+2ab=9ab
a²+b²=9ab-2ab
a²+b²=7ab
log(a²+b²+2ab)=log(9×a×b)
comparing both side
a²+b²+2ab=9ab
a²+b²=9ab-2ab
a²+b²=7ab
Kshitijydv:
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