Math, asked by ktipparamp2t1fz, 1 year ago

If log (a + b)^2 = log 9 + log a + log b, then a^2 + b^2 =

Answers

Answered by abhi569
4
log (a+b)^2 = log (9*a*b) 

log (a+b)^2= log (9ab) 

(a+b)^2 = 9ab

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by formula, (a+b)^2 = a^2 +b^2 +2ab

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a^2 + b^2 +2ab = 9ab

a^2+b^2 = 9ab -2ab

a^2 + b^2 = 7ab




 i hope this will help you



-by ABHAY
Answered by Kshitijydv
3
log(a+b)²=log 9+log a+log b
log(a²+b²+2ab)=log(9×a×b)
comparing both side
a²+b²+2ab=9ab
a²+b²=9ab-2ab
a²+b²=7ab

Kshitijydv: But why you have choosen my answer as a brainlist
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