if log(a+b/3)=1/2(log a+log b) then prove that a square + b square= 7ab
Answers
Answered by
1
Answer:
log a+b/3=1/2(logab)
log a+b/3=log(ab)1/2
(a+b)power2/3power2=ab
(a+b)power2/9=ab
(a+b)power2=9ab
a power2+2ab+b power2=9ab
a power2+b power2=9ab-2ab
a power2+b power2=7ab
Similar questions