If log a+b_3=1/2(loga+logb) then the value of a/b+b/a is
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Step-by-step explanation:
log[a+b/3]=1/2[loga+logb]
2log[a+b/3]=log[ab]
log[a+b/3]^2=log[ab]
[a+b]^2/9=ab
a^2+b^2+2ab=9ab
a^2+b^2=7ab
dividing by ab
a/b+b/a=7
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