if log(a+b/4)=1/2log(a+b) then proved that a^2+b^2=14ab
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Ok so here we go :)
∴ 2log [(a + b)/4] = log (ab)
∴ log [(a + b)/4]^2 = log (ab)
∴ [(a + b)/4]^2 = ab
∴ (a^2 + 2ab + b^2)/16 = ab
∴ a^2 + 2ab + b^2 = 16ab
∴ a^2 + b^2 = 14ab
Voila! Thus it is proved :)
Hope this helps !!!!!!!!!!!!!!!!!!!!!!
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