If log(A-B/5) =1/2log a + 1/2 log b then find the value of b/a+a/b
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1
Answer:
27
Step-by-step explanation:
log(A-B/5)= log A^1/2+log B^1/2
log(A-B/5)= log[(AB)^1/2]
cancel log on both sides
A-B/5=(AB)^1/2
square on both sides
(A^2+B^2-2AB)/25=AB
A^2+B^2-2AB=25AB
(A^2+B^2)/AB=27
A/B+B/A= 27
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