Question

If log(A-B/5) =1/2log a + 1/2 log b then find the value of b/a+a/b

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Answer 1

Answer:

27

Step-by-step explanation:

log(A-B/5)= log A^1/2+log B^1/2

log(A-B/5)= log[(AB)^1/2]

cancel log on both sides

A-B/5=(AB)^1/2

square on both sides

(A^2+B^2-2AB)/25=AB

A^2+B^2-2AB=25AB

(A^2+B^2)/AB=27

A/B+B/A= 27

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