if log ( a+b/√6) = 1/2(log a+ log b) then find a/b+b/a?
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Answer:
4
Step-by-step explanation:
we have given,
log(a+b/6^1/2) = 1/2(loga+ logb)
log(a+b/ 6^1/2) = (loga+ log b)^1/2
log(a+b/6^1/2) = log(a+b)^1/2
therefore
a+b/6^1/2 = (a+b)^1/2
a+b = [(a+b)^1/2][6^1/2]
take square on both sides
a^2 + b^2 +2ab = 6ab
a^2 +b^2 = 4ab
a/b + b/a = 4
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