if log (a+b) =log a+ log b then a=
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log(a+b)=log a+log b, then a
log(a+b)=log(ab), which gives us
a+b=ab
(a+b)ab=1
aab+bab=1
1a+1b=1
1a=(b−1)/b
Therefore
⟹a= b/(b-1)
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