If log (a-b) = log a-log b, then what will be value of a in terms of b?
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Step-by-step explanation:
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Answer:
b= (a±√a²-4a )/2
Step-by-step explanation
i am not quite sure about the answer so please read the solution only if the answer is correct.
loga-log b can b written as log(a/b)
log (a-b)= log (a/b)
a-b=a/b
b²-ab=a=0
now this is a differential equation in terms of b ,
you may now use the formula for finding the roots of equation to get the value of b
the formula is -> for equation of ax²+bx+c =0,
x={ -b ±√b²-4ac}/2a
using this you will get the above mentioned answer.
do let me konw if the answer is correct!
choicebussiness:
i have written an = instead of + so the correct equation is b*2 -ab+a=0
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