If log(a+b)=loga+log b log(a+b)=loga+log b , then write 'a' in term of
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If log(a+b)=loga+logb, then
log(a+b)=log(ab), which gives us
a+b=ab
(a+b)ab=1
aab+bab=1
1a+1b=1
1a=(b−1)b
Therefore
⟹a=b(b−1)
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