if log a+log b=log(a^2+b^2) then proved that (a+b) ^2=3ab
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Here's The Answer
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Given :
log a + log b = log ( a² + b² )
To prove : ( a + b )² = 3ab
Solution :We know, log x + log y = log ( xy )
=> log a + log b = log ( a² + b² )
By using above logarithm property
=> log ( ab ) = log ( a² + b² )
Cancelling log both sides.
ab = a² + b²
adding 2ab on both sides
ab + 2ab = a² + b² + 2ab
on R.H.S, ( a² + b² + 2ab ) can be written as ( a + b )²
ab + 2ab = ( a + b )² 3ab = ( a + b )²
Hence Proved.
Hope It Helps.
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