Question

If log ax²-5x+8=2 thenx=​

Answer 1

Answer:

Step-by-step explanation:

Question loga^x^2-5x+8 to the base a =2.

Ans: logarithm should be change in to exponent form

So!!

a^2=a^x^2-5x+8

If braces equal then exponents should be equal

2=x^2-5x+8

x^2-5x+6=0

Factorise then we get

x=2 or 3