If log base 2 ( log base 3 ( log base 2 X) = 1 , then X is equal to
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Given : log₂(log₃log₂X) = 1
To Find : Value of x
Solution:
logₐa = 1
log₂(log₃log₂X) = 1
Let say y = log₃log₂X
=> log₂Y = 1
=> Y = 2
Hence
log₃log₂X = 2
Let say
Z = log₂X
=> log₃Z = 2
logₐb = x => aˣ = b
=> Z = 3² = 9
Z = log₂X
=> log₂X = 9
=> X = 2⁹
=> X = 512
Value of X is 512
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