Question

if log base 4 256+log base 3 81-log base 2 x=0 then find x​

Answer 1

Given:

log base 4 256+log base 3 81-log base 2

To find:

The value of x

Solution:

From given, we have,

log base 4 256 + log base 3 81 - log base 2

First, separately compute the log values.

So, we have,

log base 4 256

256 = 4^4

log base 4 4^4

4 log base 4 (4)

4 × 1

4

log base 3 81

81 = 3^4

log base 3 3^4

4 log base 3 (3)

4 × 1

4

log base 2 (x)

Now combine all the equations once.

log base 4 256 + log base 3 81 - log base 2  = 0

4 + 4 - log base 2 x = 0

8 - log base 2 x = 0

8 = log base 2 x

x = 2^8

x = 256

Therefore the value of x is 256

Answer 2

Answer:

256 (answer)

Step-by-step explanation:

but in options there is no aption of 256