If log (m + n) = log m + log n, then :
A) mn = 1
B) m = -n
C) m/(m - 1) = n
D) m/n = 1
Answers
Answered by
10
Answer:
If logm+logn=log(m+n), find m in terms of n
We can write this as: log(mn)=log(m+n)
∴mn=m+n
Subtracting n from both the sides we get,
mn–n = m
n(m−1) = m
m/m-1 = n
→ Option C is the correct solution.
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Answered by
7
Step-by-step explanation:
(C) m/(m - 1) = n
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