Math, asked by Anonymous, 4 months ago

If log (m + n) = log m + log n, then :
A) mn = 1
B) m = -n
C) m/(m - 1) = n
D) m/n = 1​

Answers

Answered by Anonymous
10

Answer:

If logm+logn=log(m+n), find m in terms of n

We can write this as: log(mn)=log(m+n)

∴mn=m+n

Subtracting n from both the sides we get,

mn–n = m

n(m−1) = m

m/m-1 = n

Option C is the correct solution.

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Answered by Anonymous
7

Step-by-step explanation:

(C) m/(m - 1) = n

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