Question

If log (m+n)= log m+long. Show that m=n/n-1

Answer 1

this is the answer . i hink so

Answer 2

Given,

log(m+n) = logm + logn

log(m+n) = log(mn)

m+n = mn

n = mn - m

n = m(n-1)

m= n/(n-1)

{Properties Used :-}
loga + logb = log(ab)