Question

If log(N)^3 - log(2N)= 3log(3)-log(6),then find value of N

Answer 1

log(N)³ - log(2N) = 3log(3) - log(2 × 3)
use concept ,
loga^n = nloga
and log(mn) = logm + logn
now
3logN - log2 - logN = 3log3 - log2 - log3
2logN = 2log3
logN = log3
N = 3