Question

If log n to base 6-log(n-1) to base 6=log3 to base 6,then n=
Please help me....​

Answer 1

Formulae used in the sum are -

$log_{a}(m) - log_{a}(n) = log_{a}( \frac{m}{n} )$

${a}^{ log_{a}(m) } = m$

$log_{a}(n)$

》

${a}^{x} = n$

hope it helps ❣

Answer 2

Answer:

n/n-1 =3

3n-n =3

2n=3

n = 3/2