Question

If log (p+q)(p-q)=-1; then find value of:log (p+q)(p^2-q^2)

Answer 1

Answer: -1 + log(p+q)

Step-by-step explanation: infinite no. of solutions via archimedian property.

Answer 2

Answer:

$\red {Value \: of \: log(p+q)(p^{2}-q^{2})}\green {=log (p+q) - 1 }$

Step-by-step explanation:

$Given \: log (p+q)(p-q) = -1$

$\implies log (p^{2} -q^{2}) = -1 \: ---(1)$

$Now, \red {Value \: of \: log(p+q)(p^{2}-q^{2})}$

$= log (p+q) + log(p^{2}-q^{2})$

$\boxed { \pink { Since, log \:(mn) = log m + log n}}$

$= log (p+q) - 1 \: [ From \: (1) ]$

Therefore.,

$\red {Value \: of \: log(p+q)(p^{2}-q^{2})}\green {=log (p+q) - 1 }$

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