if log root x = 1/2 log 8, log y squared = 2log2 find the value of x+y
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log √x = 1/2 log (8)
log √x = log (8)^(1/2)
log √x = log √8
So, x = 8
Now, log (y²) = 2 log (2)
log (y²) = log (2²)
So, y = 2
So, x + y = 8 + 2 = 10
log √x = log (8)^(1/2)
log √x = log √8
So, x = 8
Now, log (y²) = 2 log (2)
log (y²) = log (2²)
So, y = 2
So, x + y = 8 + 2 = 10
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Answered by
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Answer: 10
Step-by-step explanation:
log √x = 1/2 log (8)
log √x = log (8)^(1/2)
log √x = log √8
So, x = 8
Now, log (y²) = 2 log (2)
log (y²) = log (2²)
So, y = 2
So, x + y = 8 + 2 = 10
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