Question

If log tan A + log tan B =0 then find log sin (A+B) where A,B are acute angles

Answer 1

Step-by-step explanation:

logA+logB=logAB

log tanA+log tanB=0

log(tanA.tanB)=0. {we know what (log1=0)}

then

log(tanA.tanB)=log1

tanAtanB=1

tanA=1/tanB

tanA=cotB

tanA=tan(90-B)

A=90-B

A+B=90

so

sin(A+B)=sin90=1

Answer 2

Hope this helps you.........!!!!!!!!!!!!!!!!