Question

If log V + log 3 = log π + log 4 + 3 log r , find v in terms of other quantities .

Answer 1

$log(v) + log(3) = log(\pi) + log(4) + 3log(r) \\ \\ \\ = > log(v \times 3) = log(\pi \times 4 \times {r}^{3} ) \\ \\ => 3v = 4\pi {r}^{3} \\ \\ => v = \frac{4}{3} \pi {r}^{2}$

Answer 2

$log v + log3 = log\pi + log4 + 3log r$
=>$log \: v = log\pi + log {r}^{3} + log4 - log3$
=>$log \: v = log \: \pi {r}^{3} + log \frac{4}{3}$
=>$log \: v = log \: \frac{4}{3} \pi {r}^{3}$

As logarithm on both sides cancel , we get
$v = \frac{4}{3} \pi {r}^{3}$

Hope it helps you