Question

if log(x-1)+log(x+4)=log(3x+5), then what is the value of x

Answer 1

.•♫•♬•[ welcome to the concept of logarithm.....].•♫•♬•

we know that

log (ab) = log a+ log b

solution :

$log(x - 1) + log( x + 4) = log(3x + 5)$

$log(x {}^{2} + 3x - 4) = log(3x + 5)$

this implies ,

$(x {}^{2} + 3x - 4) = 3x + 5$

$\: x {}^{2} = 9$

then X = 3 or -3

I hope it help you

otherwise report it

Answer 2

Answer:

log (ab) = log a+ log b

solution :

log(x - 1) + log( x + 4) = log(3x + 5)log(x−1)+log(x+4)=log(3x+5)

log(x {}^{2} + 3x - 4) = log(3x + 5)log(x

2

+3x−4)=log(3x+5)

this implies ,

(x {}^{2} + 3x - 4) = 3x + 5(x

2

+3x−4)=3x+5

\: x {}^{2} = 9x

2

=9

then X = 3 or -3

I hope it help you