if log (x - 1( to the base 0.3 lesser than log (x - 1 ) to the base 0.09 then x lies in the interval .
please answer fast
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Answer:
Hey mate here is your answer...
Step-by-step explanation:
Given,
log
0.3
(x−1)<log
0.09
(x−1)
Upon applying log rules, we get,
log
0.3
(x−1)<log
0.3
(
x−1
)
⇒x−1>
x−1
and
x−1
>0
Now,
x−1>
x−1
(
x−1
)
2
<(x−1)
2
x−1<x
2
−2x+1
x<1orx>2Now,
x−1≥0:x≥1
Overlapping all the intervals, we get,
x>2
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