Question

If log(x)=15.59 then find x​

Answer 1

Answer:

Well, just resort back to the definition of the logarithm:

logxy=z is equivalent to xz=y

In this case, you haven’t specified the base. I know, most students nowadays learn in their classrooms that an unspecified base on a logarithm means log with a base 10, but many others interpret it to actually be log with a base e , so I’ll just give both answers:

Assuming you are talking about log10x,

x=10−1.766

x≈0.01713957307

Assuming you are talking about logex,

x=e−1.766

x≈0.17101568526

And there are your answers! It is funny that they are really kinda similar, now that I look at them…

Hope This helps you mate ☺️

#Siddharth here!

Answer 2

Answer:

Antilog 15.59 is the number whose logarithm is equal to 15.59.

If y is the number whose logarithm is 15.59, then log X = 15.59. This is equivalent to x = 10^15.59.

. So we have:

antilog 15.59 = 10^15.59 = 3.89045145E15