If log x = -2.0258, find x.
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Solution
In order to find the value of x using antilog-table, the decimal part (i.e., the mantissa) must be made positive. For this we proceed as follows:
Calculations
log x = -2.0258 = - 3 + 3 - 2.0258
= - 3 + .9742 =3.9742
Therefore, x = antilog 3.9742.
Now, from antilog table we get the number corresponding to the mantissa
.9742 as (9419 + 4) = 9423.
Again the characteristic in log x is (- 3).
Hence, there should be two zeroes between the decimal point and the first significant digit in the value of x.
Therefore, x = .009423.
In order to find the value of x using antilog-table, the decimal part (i.e., the mantissa) must be made positive. For this we proceed as follows:
Calculations
log x = -2.0258 = - 3 + 3 - 2.0258
= - 3 + .9742 =3.9742
Therefore, x = antilog 3.9742.
Now, from antilog table we get the number corresponding to the mantissa
.9742 as (9419 + 4) = 9423.
Again the characteristic in log x is (- 3).
Hence, there should be two zeroes between the decimal point and the first significant digit in the value of x.
Therefore, x = .009423.
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