Question

If log(x^2+ 1) = log(2x) then x =​

Answer 1

Step-by-step explanation:

$log( {x}^{2} + 1 ) = log(2x) \\ \\ remove \: \: log \: \: from \: \: both \: \: sides \\ \\ ( {x}^{2} + 1) = 2x \\ \\ {x}^{2} - 2x + 1 = 0 \\ \\ {x}^{2} - 2 \times x \times 1 + {1}^{2} = 0 \\ \\ (x - 1) {}^{2} = 0 \\ \\ (x - 1)(x - 1) = 0 \\ \\ then \: \\ x = 1 \: \: and \: \: 1$