if log(x^2 - 21) =2 show that x= +-11
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Answered by
79
log(x²-21)=2
10^2=x²-21 (writing the logarithm in exponential form)
x²-21=100
x²=100+21
x²=121
x=√121=±11
10^2=x²-21 (writing the logarithm in exponential form)
x²-21=100
x²=100+21
x²=121
x=√121=±11
Answered by
43
Hey
Here's your answer !!
log ( x^2 - 21 ) = 2
=> log ( x^2 - 21 ) = log 100
Taking anti logarithm both sides ,
=> ( x^2 - 21 ) = 100
=> x^2 = 100 + 21
=> x^2 = 121
=> x = +- 11 . ( proved )
Hope it helps !!
Here's your answer !!
log ( x^2 - 21 ) = 2
=> log ( x^2 - 21 ) = log 100
Taking anti logarithm both sides ,
=> ( x^2 - 21 ) = 100
=> x^2 = 100 + 21
=> x^2 = 121
=> x = +- 11 . ( proved )
Hope it helps !!
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